Recent content by EBBAzores

Homework Statement During an experiment using Soxhlet Method to extract cholesterol from egg yolk, also using dicloromethane as a reagent, we crush half boiled egg yolk and put 80 cm3 of dicloromethane. Homework Equations Then comes a question which is assuming the maximum of absorption of...

The angular momentum will variate it self so by saying that, there will be a torque due to the variation and with the torque we can calculate de work of the bullet and by that the kinetic energy of rotation

Either way thanks for the help you've been given me

Vr/e=Vr/c + Vc/e... Seriously I'm feeling so stupid right I have an exam in 3h hours and I'm feeling like a don't know a thing!

So the Vr/e + Vc/e = Vr/c

Homework Statement A bullet with 5 g of mass and a velocity of 100m/s goes through a disk that was rested initially the disk is solid and as a radius r=20cm. It's 2cm thick and as a 2kg mass that can spin with no friction in an axis that goes through the center. The bullet goes trough the...

So from what I draw I understood that the actual velocity diagram is given by Vc/e = Vr/e + Vr/c but besides that the results that I obtained before were right

Ok so here I am again ready to finish it already. Since we know that y=Acos(ωt+\phi) so (d2y)/(dt2)=-Aω2cos(ωt+\phi) we can easily get that -Aω2cos(ωt+\phi)= -(k/m)(Acos(ωt+\phi)) from that expression we obtain that ω2=k/m concluding that ω=√(k/m) we also know that T=2π/ω=2π√(m/k)...

Vr/c = Vc/e + Vr/e so by that logic Vr/c = 50/sin(60) and of course Vr/e = Vr/c cos(60) = (50cos(60))/sin(60) and that's the answer by this logic right?

VC/E plus VR/E? That's equal to the 3rd vector

Homework Statement A car travels to east with 50 km/h. It's rainning vertically in relation to the Earth. The raindrops on the lateral windows of the car make a 60 degree angle with the vertical. Determine the velocity of the raindrops in relation to: a) The Earth b) The car Homework...

This might be a REALLY wild guess but where it goes xD (d2y)/(dt2) = -(K/m)y so that meand that dt2 =(d2)y/(-k/m)y the y's disappear so I'll assume now that dt is an aproximation to the period T and that the minus sign before k doesn't really interest us so we'll exclude it therefore...

I've solved it. Now I get the actual S.H.O. equation which is now (d2y)/(dt2) + (K/m)y = 0 That part I understood but now I want to know why the period of oscillation is T=2π√(m/k) how do we demonstrate that? I can't figure it out sorry for wasting your time with this, maybe I'm really...

Ok one problem down, so i'll assume that g isn't relevant since I change variables for the S.H.O. but now how do we prove that the period is in fact the above one? P.S. Thanks for welcoming me in here =)

I have a question that's being bugging me around. This might be simple but I can't figure it out. If there's a spring hanging from the ceiling and we want to prove that there's a Simple Harmonic Oscilation then why don't we account for the gravitational force? The sum of forces equals to mass...