Recent content by eitan77

In that case I am not sure how I should continue from here.

That's what I did. the minimum requierd angle is not ## arctan (d'/2F)## ?

Thank you! I will be more clear, the situation I described in the calculation refers to angles ## \phi ## in the quarter of the positive plane ( ## 0<= \phi < \pi /2 ## ) and ## 0<= \theta < \pi /2 ## . ##\theta _m ## - is the maximal ##\theta## (same with ##\phi ## ) I am not letting...

This is not specified in the task, I guess it can be assumed that this is the simplest case that can be thought of.

So does that mean you think the solution I gave in #12 is incorrect? After going through it again, I'm starting to be convinced that the solution is actually correct.

##d/2F = U/2D## ##d'/2F = 0.01U/2D## d' - the size of the object's reflection on the image sensor ##pixels size = d/N ## since we want N to be minimal, the pixel size should be maximal: pixels size = d' hence : ## N = d/(pixels size) = d/d' = 100 ## My final answer does not depend on U...

Yes, that is what is required of me.

Thank you again, Does that make sense to you? For some reason I feel that something is wrong.

Thanks, regarding the second question I assume not. I'm not sure, the only thing I can think of is to separate the cases where the body rotates only around the x-axis and then only around the y-axis, and in both cases check what happens when the forces on the two legs farthest from the axis of...

one more question, how can I find the maximal angles ##\theta and \phi ## in which the crane is still stable? it seems I'm missing equations: f_11 +f_22 +f_21 +f_12 =mg +w -h(f_22 +f_12 ) +mg*h/2 -##w[50cos( \theta )sin(\phi )-h/2 ]=0 ## -mg* l/2 + l(f_11) +f_12 ) +##w[50cos( \theta...

To be honest I'm not sure why it's attached this way

It can be assumed that the movement is quasi-static. there is no requirement that the boom attach to the vehicle body in the center, the only requirement is to find the optimal way to attach the boom to the crane platform to reduce the risk of the crane turning over.

Thank you very much to all of you, you helped me a lot!

My intuition says that the bottom half of the circle should be ruled out, But I'm not sure how I'm supposed to see this mathematically. (if I am right) And thank you very much for your patience.