Recent content by elbowgrease6

Okay, I solved it. Theta = 33.56 degrees Ta= 280.9 N Tk= 168.54 N Could anybody check and see if those seem right?

I think that is where I have gone wrong. I have written several equations: -Tkx + Tax = 0 Tky + Tay - W = 0 -Tk(cos theta) + Ta(cos 60) = 0 Tk(sin theta) + Ta(sin 60) -150 N = 0 I think my main confusion is, is there a y term for the tensions? Because they do not tell you how much above the...

Homework Statement Consider the two cables suspending a leg with a cast in the drawing. If the leg and cast weight 150 N, and the angle of the ankle cable is 60 degrees above the horizontal, what are the cable tensions and the angle of the knee cable from the horizontal such that the leg is...