Recent content by eliUCV

Ok, but E never can be less than ## V_{min}## for any ##V(x)##, right??

Yes, could E be less than V_max ?

Thanks :D ## V(x) = - \alpha \delta(x) ## where ## \alpha > 0 ## I think it is important to say that it is time-independent Schrödinger's Equation

Hi, I have a question, why when we study the Delta-Function Potencial we can treat with ##E < V##, since the following relation says ##\frac{d^2 \psi}{dx^2} = \frac{2m}{\hbar^2} (V - E) \psi## And do not allow it? or it is just ##E <...