Recent content by ellyb

A flowerpot is knocked off a balcony 20.0m above the sidewalk and falls toward an unsuspecting 1.75-m tall man who is standing below. How close to the sidewalk can the flowerpot fall before it is too lat for a warning shouted from the balcony to reach the man in time? Assume the man below...

KE= 1/2 2.0E6 N/m * (.3)^2 Is this the right formula to use for the mechanical energy last part?

If the spring is compressed by only 0.30-m, find the change in the mechanical energy due to friction. How do i find this part?

Is this right? f=-kx=-2.0E6*0.4=8.0E5N a=F/m=8.0E5N/1300Kg=615.4 kg.n

How do i find the maximum acceleration?

oh right...so it would be x= squar(127400(2)/2.0E6)=.4 m

A 1300-kg car starts at rest and rolls down a hill from a height of 10.0-m. It moves across a level surface and collides with a spring-loaded guard rail designed to bring the car safely to a stop. The spring has a spring constant of 2.0E6N/m. Neglecting any losses due to friction, and ignoring...