Recent content by emillindberg
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Graduate Entanglement swapping and Bohmian mechanics
I think neither option quite follows. The future swap does not need to cause the earlier A/D outcomes, and the earlier outcomes do not cause the later swap to succeed. The swap result sorts the already recorded A/D data into subensembles, which is where the Bell-state correlations show up. The...- emillindberg
- Post #56
- Forum: Quantum Interpretations and Foundations
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Tick-borne diseases - recent increases in cases
No need for apologize. I was just kidding. But still to the point message conveys clear message.:-p- emillindberg
- Post #19
- Forum: Biology and Medical
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Tick-borne diseases - recent increases in cases
Yeah, the newest reply is a bit much. It reads more like a paper than a forum post. I do think the thread has shown something interesting though. Whether climate is the main driver or one factor among several, a lot of people are noticing ticks in places where they barely saw them years ago. The...- emillindberg
- Post #15
- Forum: Biology and Medical
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Undergrad Non-Linear Infinite Resistor Ladder
You're right, I missed that in my earlier comment. I was thinking along the right lines with the recurrence, but I overlooked the result you had already derived in post #8. Thanks for catching that. I'll go back through the derivation before commenting further.- emillindberg
- Post #26
- Forum: Electromagnetism
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Undergrad Non-Linear Infinite Resistor Ladder
The recurrence relation seems like the natural way to attack this rather than relying on numerical convergence alone. For a finite ladder, the equivalent resistance is rational, so the interesting part is what happens as the number of sections tends to infinity. If the ladder is self-similar...- emillindberg
- Post #23
- Forum: Electromagnetism
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Undergrad Prove that 1 + NOT (1 + NOT x) = x
The easiest way to see this is to treat n bit numbers as arithmetic modulo 2^n. For any n bit number b, NOT b changes every 0 to 1 and every 1 to 0. Numerically, that means NOT b = 2^n - 1 - b. So 1 + NOT b = 2^n - b, which is equivalent to -b modulo 2^n. In other words, NOT b + 1 gives you...- emillindberg
- Post #6
- Forum: General Math
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Graduate Is the deformation in Eq. 56 really innocuous?
I think your concern is reasonable. A shift inside sign(φ+α) is not obviously a harmless reparametrization, because the sign operation makes the threshold change physically relevant to the resulting dichotomic observable. In particular, allowing four independent α values seems capable of...- emillindberg
- Post #2
- Forum: Quantum Physics