Recent content by Emmanuel

I've solved this now, covered Archimedes principle in college so I've managed to do it but thanks for the input

Is mass: volume × density? If so the mass of iron would be 0.06 × 7800= 468 To be completely honest I'm not sure if the units Do I just add the volume of iron and the buoy together to get the total volume? Seems too simple to be that.

Ok so the surface area is 6.03 So i times by 0.01m rather than 10mm Which is 0.0603 ?

Bloody hell I've already made a mess of it ha So the volume of the buoy alone would be 1.0048 And the volume of the iron is 60.288 Where do I go from there?

Volume would then equal 60.288

Sorry for some reason I had a sphere in my head So it would be 6.0288? (2•π•r^2 + π•d•h) 2 × 3.14 × 0.4^2 + 3.14 × 0.8 × 2

So volume of iron plate is 20.096 sorry

So to find the surface area it is 4•π•r^2 4 × 3.14 × 0.4^2= 2.0096 And the volume of the buoy 4/3 × 3.14 × 0.4^3= 0.267 Do I just add these together to find total volume

There is no figure that comes with it and I have provided all the information I was given. I think to calculate the volume of the buoy it would be 4/3•π•r^3 but I'm not sure how I would do this with the iron plate or put the two together Please forgive me I have only just started this...

Homework Statement A cylindrical buoy floats in sea water with its axis vertical so that it's three-fourths submerged. The buoy is 0.8m in diameter and 2m in height. Its fabricated from iron plate 10mm thick. Calculate the mass of iron chain securing the buoy. The relative density of iron is...