What I am trying to find is the equation for the angle of reach for a projectile fired from an elevated position. If you fire a projectile at an angle q from the same height as your target and you know the distance, x to your target and the initial velocity v you get
q = 0.5[arcsin(gx/v^2)...
Homework Statement
A cannon is firing from an elevated position 100 m above a target 800 m away. The ititial velocity of the cannon is 500 m/s.
Homework Equations
Vx = VCOSq
Vy = VSINq
a = (Vf - Vi)/(t)
Vf = Vi + a t
s = 0.5 (Vo +Vf)t
Vf2 = Vo2 + 2aS
S = Vit + 0.5at2...
water balloon launcher
I am trying to work out the same thing with the goal of letting my students practice a little water balloon artillery. Try launching the balloon straight up. Calculate the total time of flight. take half the time and multiply that by 9.8 m/s/s that should be the speed...