Recent content by endykami
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Differential calculus, solve for y: 4(y''y'')+(y'y')-1=0
suppose y''=r^2=s y'=r 4(y''y'')-(y'y')-1=0=4(r^2)^2-(r^2)-1=4(s^2)-s-1 s=(-b±√(b^2-4ac))/2a s=(1±√17)/8 y=∫∫sdx=∫∫((1±√17)/8) dx=(1±√17)/8)(1/2)x^2+c1x+c2- endykami
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- Calculus Differential Differential calculus
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- Forum: Calculus and Beyond Homework Help