I got the IABsinθ equation from class. I gave this problem another try.
I set it up so Kx = ILBsinθ. I rearranged to get K = ILBsinθ/x... Plug and chug (2.90)(0.400)(1.88)(sin55)/(0.0043) = 415.4
Am I getting closer?
Homework Statement
Consider a wire loop in a 1.88 T magnetic field (coming out of the board at a 55.0° angle). The loop is 0.300 m tall and 0.400 m wide, carrying a 2.90 A current traveling in a clockwise direction. The loop feels a torque that causes the spring to compress. If the spring is...