Recent content by Engineering101

So I have one attempt left and want to make sure my answer is correct, so double checking me would be super awesome! You are given a pendulum composed of a 0.030 kg mass on the end of a 0.42 m long massless string. The pendulum is moved 25° from the vertical and released. Find the tension in...

So, Fradial= -T + mgsin(65) T=mgsin(65) T=.27 N

So I have one attempt left and want to make sure my answer is correct, so double checking me would be super awesome! You are given a pendulum composed of a 0.030 kg mass on the end of a 0.42 m long massless string. The pendulum is moved 25° from the vertical and released. Find the tension in...

Thanks for the help! I genuinely appreciate it :) I used Fg-Ff=ma mgsin(26.6)-umgcos26.6)=ma 9.8(sin26.6)-.32cos(26.6)=a a=1.41 t=.82s

Physics Help Greatly Appreciated -- Block sliding down ramp A 7.7 kg block is on an incline with a coefficient of static friction of 0.50. The angle that the ramp makes with the horizontal is increased gradually, until the block begins to slide down the ramp. If you know that the coefficient of...