Recent content by EnricoHendro

Hello there, My attempted explanation/solution is : “Torsional strain is caused by the tendency of the electron clouds in the interacting groups to repel each other, making it relatively difficult to rotate a group towards and through another group, as the repulsive force provides resistance to...

Hello there, I am also currently reading stewart’s multivariable calculus. And I am also working not just studying. Plus I am also studying physics and chemistry. I personally like to do all the odd number exercises (the ones that have the solutions on the back of the book so that I can check...

Hi there, I am currently reading introduction to Chemistry fourth edition by Bauer, Birk, Marks. what do you guys think about this book? is it a good book? I am doubting the quality of the book because I found one wrong statement about the reaction of Alkaline Earth Metals. It said "Alkaline...

oh I see. Yes, my textbook taught me that the change in internal energy is Q+W. I see. Thank you for your answer

here is the method that my book used

In the book, it states W = -Q since final temperature after the whole cycle equals to the initial temperature (300K), therefore, the change in internal energy is zero. Using 1st law of thermodynamics, W=-Q. The book evaluates the Q for each cycle, and then using change in internal energy = 0...

Hello there, is my solution for part d logically correct? Here is my attempt at the solution : Part a : where : P1 = 3P2 Part b : Since P1=3P2, therefore, T1=3T, where T=300K. Thus, T1=900K Part c : Because the final pressure at the end of the cycle is exactly the same as the pressure at...

I am using physics for scientist and engineers 9th edition by Serway and Jewett

I meant, solve for F using mg = 2Tsin##\alpha## so we'd get equation ##F=2T\sin(\alpha+\theta)-2Tsin##\alpha## I got my wording all over the place, I apologise. I meant to say solve for F.

by x I mean the ##\alpha## .

Oh i see, so we take the trigonometric form of mg which in this case is 2Tsin(x) and then solve it for F. Am I getting this right?

oh, I see, so basically, (ignoring our assumption that this particular problem has a horizontal oscillation) because the oscillation would take place about the equilibrium point where the mass naturally hangs (in which the gravitational force is canceled by the balancing force that makes the...

I see. I still don't quite understand the part "by taking the strings as angling down to the mass at equilibrium, then just considering perturbations from that position".

Hello there, I am wondering, in this solution, I guessed that the restoring force is given by that equation in the problem because the vertical component of the force acting on the ball is -2Tsin(x). since sin(x) = y/L with L being the hypotenuse part of the triangle formed by displacing the...

oh I see. Yeah, I don't actually want to delay my study on oscillations and physics as a whole. I always thought physicists kind of have all the necessary math (like they don't have to learn the math as they move forward). Thank you for sharing your trick I will try to digest your method.