Recent content by Epic Mango

The velocities you're using for kinetic energy are wrong; try to use the same variable names as with your momentum equation.

Sorry, but 20 is not the answer. In fact, there is a much easier way to do this problem, using one formula. The formula is: R = vi2*sin(2θ)/g R is the range, or your horizontal distance. If you check with this, it gives you the value of vi as ~33.6 m/s. Generally, however, the "long" way of...

Hi, I'm Joon. I'm new to these forums. Sorry I posted this after my first post. :( My bad, didn't check my Email. So I know most of mechanics, and I'm good with most problems, I think. I just have to think a bit about most of them. I don't know theoretical, though. I'm only in 9th grade, after...

The trick to solving these problems are detaching horizontal movement and vertical movement. What I mean by this is thinking about each dimension separately. Okay, so we first list what we know. θ = 30 degrees, d = 100 meters, g = -9.8 meters per second squared We also need these kinematics...