Recent content by erox

Ok so using the equation you gave me i subtracted the height 52m -10m from the ground resulting as 42.1m. v2^2=11.5m/s^2+2(9.8)(42.1m) v2=30.94 m/s Would this be correct or would i have to a use the range equation for any reason R=x^2+y^2?

Homework Statement I have this question regarding how i would do the second part of this question as i already know how to do the first part ,but i can't seem to find an approach to the second."What is the speed of the stone at a height of 10m from the ground?" A stone is thrown off the...