Recent content by Etrujillo

Im assuming 12m is the radius so \frac{270}{360}pi×12squared=108 pi Am i correct?

So far i have. 12) area of full circle is πr² area of sector is (120/360)(πr²) or 12π 13) same area is (270/360)(πr²) Am i correct?

So far i have. 14) area of sector is πr²/3 = 12π length of chord. that triangle has two sides of 6 and angle of 120º split the triangle in two right triangles with angle of 120/2 = 60 and hyp=6. other (longer) side is: sin 60 = x/6 s = 6 sin 60 = 6(√3/2) = 3√3 third side is s = 3 cos 60 =...

To start with problem #5 i cut the shape Into 2, a triangle and a square, i know that the additional leg length to the triangle can be found by subtracting base 1 and base 2=4 so i have a triangle with a hypotenuse of 8 inches, 1 leg=4 and now i have to find the length of the other leg. The...

The radius i believe is 12m so when i plug in your formula i get 108pi as the answer. Am i correct?

If i use a2 + b2 = c2 I get 8^+4^=80 80 would be the other leg? Would this be considered a right triangle? So one leg would =4 (10-16) and the other 80?

I think the answer to number 1 is 63.0 or 60 if rounded to the nearest tenth, and i think number 2 is. 96.0 or 100 if rounded to the nearest tenth. Need help with 3 and 4. I think for 3 i would add 6 and 8 as the vertical diagonal and the horizontal diagonal would be 5 . 6+8=14 so the area...

So far i have 270/360× (pi)r^ i don't know what to do next please help.

So I've been able to solve A.12 inch B.24 inch C.75.3982 D.452.389 Cant solve e. Arc length can anyone please explain the formula. Thank you