Recent content by Evil_Kyo

In a elastic collision momentum and KE are conserved: m_1\overrightarrow{v}_1_i=m_1\overrightarrow{v}_1_f+m_2\overrightarrow{v}_2_f \frac{1}{2}m_1v^2_1_i=\frac{1}{2}m_1v^2_1_f+\frac{1}{2}m_2v^2_2_f in this case the masses are the same so we can simplify...

1- Let me ask you a question, what is the spring balance measuring? If you understand this you'll see if the tension of the string is needed or not. Think about a mass m suspended in a spring balance, what measures the spring balance? Let the balance go, what measures during the free...

As prasanna has noted i haven't selected a origin for the potential energy. h_1 and h_2 mean the initial and final position of the falling mass attached to the pulley. You don't know it but you know its difference h_1-h_2 that equals the length traveled by the falling mass 2 metres...

If I've understood correctly the two disks act as a pulley with the mass at the end of the string. If it is the case you can work it as a typical solid rigid problem calculating the angular acceleration and relating it with the linear acceleration of the mass. Then it becomes a "semi-free" fall...

It's been a long time since i studied thermo but here i go. If we have only a heat source and the initial and final states are in equilibrium, they have to be at the same temperature of the source. If the process is reversible every single step is a equilibrium state and so it has to be at the...

No, Newton's first law doesn't apply to satellites. The first law states that if the force applied over a body is null (or the sum of all forces applied are null) that body remains in rest or moving in straight line with constant speed. In this case our satellite is orbiting, so there's a...