Recent content by evsong

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    Integration by parts conceptual problem

    4f'(4) - f'(1) - [f (4) - f (1)] (4*3) - 5 - [ 7-2 ] = 2 is this right? ! :D !
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    Integration by parts conceptual problem

    I meant 4f'(4) - f'(1) - [f'(4) - f'(1)] i just forgot the ' I used integration by parts and evaluated the uv section at x=4 and x=1 then evaluated f(x) from 1 to 4
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    Integration by parts conceptual problem

    ok I need to evaluate it at the limits \left. xf'(x) \right|_1^{4} - \int_{1}^{4} f'(x) dx \left. 4f'(x)-f'(x)- [f(x)] \right|_1^{4} 4f'(4)-f'(1)-[f'(4)-f'(1)] 4*7 -(2)- [7-5] = 22 -2 = 20 how is this so far? I don't know how to incoorporate both the f'(1) and f'(4)
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    Integration by parts conceptual problem

    oh would it be u=x du=dx v= f'(x) dv = f"(x) so: xf'(x)- \int f'(x)dx I don't know how to incorporate the given f'(1) =5 and f'(4) = 3
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    Integration by parts conceptual problem

    oh would it be u=x du=dx v= f'(x) dv = f"(x) so: xf'(x)- \int f'(x)dx I don't know how to incorporate the given f'(1) =5 and f'(4) = 3 sorry for the double post. I accidently pressed submit before I was ready then clicked preview right after.
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    Integration by parts conceptual problem

    1. Suppose : f(1) = 2, f(4) =7 , f'(1)=5, f'(4) = 3 and f"(x) is continuous. Find the value of: \int_{1}^{4} xf''(x)dx Homework Equations IBP formula \int u(x)dv = u(x)v(x) - \int v(x) du The Attempt at a Solution I re-wrote the IBP formula from...
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    Integration by parts conceptual problem

    1. Suppose : f(1) = 2, f(4) =7 , f'(1)=5, f'(4) = 3 and f"(x) is continuous. Find the value of: \int_{1}^{4} xf''(x)dx Homework Equations IBP formula \int u(x)dv = u(x)v(x) - \int v(x) du The Attempt at a Solution I re-wrote the IBP formula from...