Recent content by Exus
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Find the Surface integral of a Paraboloid using Stoke's Theorem
## \iint_S (∇×\vec F)⋅\vec n \,dS = \iint_S <P, Q,\frac ∂ {∂x} (x+z) - \frac ∂ {∂y} (z-y) >⋅<0, 0, 1> \, dS = \iint_S 2\,dS = 8π ## That makes a lot of sense, thanks for the tip.- Exus
- Post #5
- Forum: Calculus and Beyond Homework Help
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Find the Surface integral of a Paraboloid using Stoke's Theorem
that's embarrassing, thank you. ## \vec r' (t) = <-2\sin t, 2\cos t, 0> ## ## \vec F (\vec r (t)) = <-2\sin t , 2\cos t, -\cos (2\sin t)> ## ## \int_0^{2π} <-2\sin t , 2\cos t, -\cos (2\sin t)>⋅<-2\sin t, 2\cos t, 0> \, dt = \int_0^{2π} (4\sin ^2 t +4\cos ^2 t) \, dt = 4 \int_0^{2π} \, dt = 8π ##- Exus
- Post #3
- Forum: Calculus and Beyond Homework Help
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Find the Surface integral of a Paraboloid using Stoke's Theorem
Homework Statement Let S be the portion of the paraboloid ##z = 4 - x^2 - y^2 ## that lies above the plane ##z = 0## and let ##\vec F = < z-y, x+z, -e^{ xyz }cos y >##. Use Stoke's Theorem to find the surface integral ##\iint_S (\nabla × \vec F) ⋅ \vec n \,dS##. Homework Equations ##\iint_S...- Exus
- Thread
- Integral Paraboloid Surface Surface integral Theorem
- Replies: 4
- Forum: Calculus and Beyond Homework Help
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Linear Algebra, subset of R2 not closed under scalar multipl
Closed under scalar multiplication means that any vector in the subset could be multiplied by a scalar and still be within the subset.- Exus
- Post #14
- Forum: Calculus and Beyond Homework Help
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Linear Algebra, subset of R2 not closed under scalar multipl
Consider the set of all vectors S = [x, y] such that x, y are integers. Does that work?- Exus
- Post #2
- Forum: Calculus and Beyond Homework Help
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Engineering Student's Transfer Journey: Mastering Math and Science
I'm an engineering student looking to transfer to university soon. Math and science have always been fun and I've just completed linear algebra, multi variable calculus and my first semester of E&M. Hello, and thanks in advance for all the advice, insight and help i may find here.- Exus
- Thread
- Replies: 1
- Forum: New Member Introductions