Recent content by ezsmith

After thinking real hard for almost 2 days. I know that my horizontal and vertical component has the same time is in flight. So I can use resolve my t initially in the horizontal component of the flight using Sx = Vicos30 t right. So wouldn't be t = Sx / Vi cos 30 Knowing my Sx is 80 and...

For my vertical component, its -35 = Vi sin30 t -4.9t^2 At this stage, how am I going to solve with Vi being an unknown instead of a value?

Oh, I think I figured it out So its, I use Vx = Vicos30° V = s/t V = 80 / t cos30° Then with this equation V = 80 / t Vicos30° I sub into my component y which is -35 = Vi sin30 t-4.9t^2 -35 = 80 sin30 t/ t cos30° - 4.9t^2 t = 4.07s Is it right?

Homework Statement This is a review question from the test I did few months back, and I need to review it for my finals. A ball is thrown from the top of a building 35m high with an initial speed of Vi at an angle 30° above the horizontal. The ball strikes the ground at a point 80m from...

Hi, I used to do all this type of inequalities but I have not practice this for almost a year and I have totally forgotten and didn't know why did the sign change. For example: If it's 3x ≤ 9 The answer: x ≥ 3 Is this right? I have actually forgotten in what circumstances we are suppose...

Homework Statement Determine the distance between the point (10,2,3) and the plane determined by the points A(2,3,0), B(3,1,4), and C(5,2,1). The Attempt at a Solution What I did was I took (B-A) and (C-B) and then I cross product (B-A) and (C-B) and I got -10i + 11j + 5k. After this step...

Sorry for the late reply and thanks for the reply algebrat and ehild.. Its really helpful as I am pretty stuck earlier. Just to make sure whether I am on the right track. After doing cross product which is -22i-22j+11k. I found the magnitude of the cross product which is 33 and then I took the...

Homework Statement Find the shortest distance between the lines r = (0,7,6) + t (-3,2,2) and the line r = (-3,6,-4) + s (2,-5,6) The Attempt at a Solution What I did was I cross product s(2,-5,6) & t(-3,2,2) then I took (0,7,6) - (-3,6,-4) After getting both answer from the 2 steps I took...

Yea finally I am able to solve it. I was having dilemma on the square root part but your advice had been really helpful. Thanks a lot HallsofIvy. Cheers :smile: I got my answer a = \sqrt{30}. I accidentally put s(1,2,-1)xt(5,a,-5) when its suppose to be s(1,2,-1)xt(5,a,5) therefore its suppose...

Homework Statement The line l has the equation r= s(1,2,-1) and the line m has the equation r= (0,1,1)+t(5,a,5). Find the value of a such that the angle between the line l and m is 60degree. The Attempt at a Solution What I did was use the equation s(1,2,-1)xt(5,a,-5) = \sqrt{1^2 + 2^2 +...

Yea, I meant by expanding the (x+h)3. I had managed to solve it using binomial theorem and it has saved me a lot of trouble. Thanks a lot Infinitum. Cheers :)

Homework Statement Should be a simple question but its really tough for me because my lecturer had never teach me before about x^3 Anyway, the question is find the first derivative by using first principle method : c) x^3+2x^2+1 Homework Equations The Attempt at a Solution I...

Never mind. I managed to solve it. Thank you for the reply :)

Homework Statement Find cartesian equations of the line of intersection of the planes x+3y-6z =2 and 2x+7y-3z=7 The Attempt at a Solution What I did first was I cross product the 2 equation and then I got 33i-9j+k Then I took both of the equation and let y = 0. After that my answer seems...

I did listen in class but the lecturer only gave notes to copy during class and there is no example given in the notes so that is why. Anyway, I managed to solved it. Thanks a lot sir.. Really appreciate it :)