Recent content by FalconKICK

I solved it yesterday on my last try. It's actually pretty easy, but I need some help with Circular Motion so I'll need to talk to my teacher about it.

Should I replace it with 1Cos(30) + 1.5m?

Hmm...i have no idea what I'm doing then.

2.4COS(30) I'm not sure either I think I'm supposed to add 1.5 to whatever answer I get not really sure.

I did this and still don't get the correct answer. One more try left the vertical velocity of the stone on release Vv = 2.4 sin 30 = 1.2m/s time to reach max height v = u+at (v=0 at max height, Vv = u) 0 = 1.2 - 9.8t t = 0.122 sec max height above release reached v^2 = u^2 + 2as 0 = 1.2^2 -...

Oh so 1cos(30) + 1.5 = 2.36602 m 1sin(30) + 1.5 = 2 m

1.5cos(30) = 1.299m 1.5sin(30) = .75m now what do I do? I don't know how to use the information that I have.

I know that the height is 1.5 m. I have the velocity components but I do not know how to find the initial position components

Part a I did it wrong because I subtracted time that I got from 1.5 (height) and for some reason it gave me the correct answer. Here's how I solved part A. 2.4COS(30) = 2.0784 2.4SIN(30) = 1.2 t =( - 1.2 + sqrt(1.2^(2) + 4(4.9)(1.5) ) / 9.8 t = .444222 1.5 - t = 1.06 I...

I solved for time which is .68912 seconds. What do you mean by how far it would go horizontally? I don't know about initial position either.

It doesn't specify but I believe it's center of the circle. For X-Component I used 1.2m/s and I used 2.0784m/s for the Y-Component. I'm really confused by this, so I don't really know what to do.

Sorry that I didn't include one. I'm trying to find a host. It'll be up shortly.

Homework Statement A stone at the end of a sling is whirled in a vertical circle of radius 1.00 m at a constant speed vi = 2.40 m/s as in Figure P4.57. The center of the string is 1.50 m above the ground. http://xs124.xs.to/xs124/08095/p4-57alt_1_285.gif I solved these: (a) What is the...

Ok I understood what you guys said and got part a but I'm still sort of confused about part b, the first part of it.

I tried that but when I input the answer into the site it says it's wrong.