Recent content by farrukh.hafeez

Underprogress...will ask for help if required. Do you know any reference which provides full expression for compatibility equations in polar coordinates by any chance? Thanks

For an axisymmetric long tube, it is said that radial displacement is independent of axial coordinate. What is the justification for this simplification?. If u, v and w are axial , tangential and radial displacements then u=u(x,θ,r) v=v(x,θ,r) w=w(x,θ,r) Where x,θ,r are polar coordinates...