Radial displacement in hollow cylinders

AI Thread Summary
Radial displacement in axisymmetric long tubes is considered independent of the axial coordinate due to the symmetry of the system. This simplification arises from the uniform loading along the tube's length, which allows for the assumption that displacements do not vary with the axial position. Discussions highlight the importance of using cylindrical-polar coordinates to analyze these conditions accurately. Participants suggest exploring problems without this independence assumption to understand the implications better. References for compatibility equations in polar coordinates are also shared for further study.
farrukh.hafeez
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For an axisymmetric long tube, it is said that radial displacement is independent of axial coordinate. What is the justification for this simplification?.
If u, v and w are axial , tangential and radial displacements then
u=u(x,θ,r)
v=v(x,θ,r)
w=w(x,θ,r)
Where x,θ,r are polar coordinates.
Due to axisymmetry all displacements are independent of θ. For a long tube ,also only radial displacement is independent of axial coordinate i.e. x axis. Why?

u=u(x,r)
v=v(x,r)
w=w(r)?
For example
See section 10.2.1 and equation 10.3 of "Mechanics of Fibrous composites" by Carl T Herakovich 1999 ISBN: 978-0-471-10636-4
 
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Welcome to PF;

For an axisymmetric long tube, it is said that radial displacement is independent of axial coordinate. What is the justification for this simplification?.
Symmetry.
http://homepages.engineering.auckla...lasticityPolar/ElasticityPolars_01_Polars.pdf

Due to axisymmetry all displacements are independent of θ.
Hmmm... I don't think so... did you leave something out?

For a long tube ,also only radial displacement is independent of axial coordinate i.e. x axis. Why?
Try a few problems without assuming the independence and see what happens (do still use cylindrical-polar coordinates though).
 
Simon Bridge said:
Welcome to PF;

Symmetry.
http://homepages.engineering.auckla...lasticityPolar/ElasticityPolars_01_Polars.pdf

Hmmm... I don't think so... did you leave something out?

Yes, you are right. I think I didnot mention axisymmetric and uniform loading along the length

Try a few problems without assuming the independence and see what happens (do still use cylindrical-polar coordinates though).

Underprogress...will ask for help if required.

Do you know any reference which provides full expression for compatibility equations in polar coordinates by any chance?[/QUOTE]

Thanks
 
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