Recent content by Fetchimus

  1. Fetchimus

    Expectation value <x> for superposition in infinite square well

    Thank you so much! I got the first part of your expression! Was not able to simplify it down to the second part though where you have cos(3ωt+π/4).
  2. Fetchimus

    Expectation value <x> for superposition in infinite square well

    Okay I think I see what you're saying. So for the RE term I have [(1-i)/2]√2/2(cosθ+isinθ)<x>12 = [(√2/2L)cosθ+(√2/2L)sinθ](2/L)(-8/9(L/π)2) which simplifies to 2RE = [√2cosθ+√2sinθ](-16L/9π2) So <x> = (1/2)L + 2RE
  3. Fetchimus

    Expectation value <x> for superposition in infinite square well

    Are you saying that, <x>12+<x>21 = <x>12 + <x>12* and that's where my sum of a complex # and it's conjugate is coming from? I totally forgot about that formula tbh. Thanks for the reminder. I'm having trouble getting the real part out. I feel as though the exp term goes away by default due to...
  4. Fetchimus

    Expectation value <x> for superposition in infinite square well

    Definitely need to take some time to let that sink in. So for part e) I have <x> = (1/2)L - (4L/9π2)(√2)[(1-i)ei(E1-E2)t/ħ+(1+i)ei(E2-E1)t/ħ]. If this is correct I'll be on my way. If you have something different I can simply go back and check my math at this point.
  5. Fetchimus

    Expectation value <x> for superposition in infinite square well

    There is also a part f) where I am asked to find <p>, but seeing as how I could simply use m(d/dt)<x> I was really just hoping to get the proper answer for <x>. I have math worked out for everything, but the typing would take forever, lol. Btw, thanks for all your help so far. It is much...
  6. Fetchimus

    Expectation value <x> for superposition in infinite square well

    For part c) I got (5/2)(π2ħ2/2mL2) For part d) I got (1/2) Spent a few hours on these because I was uneasy about not seeing t anywhere in my answer, but a buddy of mine that has done this problem before claims that these are correct. Perhaps they are not. Not entirely sure.
  7. Fetchimus

    Expectation value <x> for superposition in infinite square well

    Okay. So doing integration by parts on the integral and once again ignoring the constants for the time being, I ended up with -(L/π)2+(L/3π)2. Is this the correct result when evaluating the integral from 0 to L?
  8. Fetchimus

    Expectation value <x> for superposition in infinite square well

    I believe it's ei(E1-E2)t/ħ. I left it out for the sake of pinpointing the integral itself.
  9. Fetchimus

    Expectation value <x> for superposition in infinite square well

    Homework Statement A particle of mass m, is in an infinite square well of width L, V(x)=0 for 0<x<L, and V(x)=∞, elsewhere. At time t=0,Ψ(x,0) = C[((1+i)/2)*√(2/L)*sin(πx/L) + (1/√L)*sin(2πx/L) in, 0<x<L a) Find C b) Find Ψ(x,t) c) Find <E> as a function of t. d) Find the probability as a...