Homework Statement
A 31.0 kg child runs with a speed of 2.80 m/s tangential to the rim of a stationary merry-go-round . The merry-go-round has a moment of inertia of 520 kg\cdot m^2 and a radius of 2.51 m. When the child jumps onto the merry-go-round, the entire system begins to rotate...
That was right! Thanks so much. If you wouldn't mind I still can't get part two. I know that a_c and a_t are perpendicular to each other, so I was thinking I should use trigonometry to find the direction of acceleration. I tried arctan(a_c/a_t), but that was no good.
Yes, I meant alpha. And I squared it because I was accidentally looking at the formula for centripetal acceleration when I was writing the tangential acceleration formula. Is that squared term the root of my problems?
I did:
a= sqrt(a_c^2+a_t^2)
a_c^2=r*w^2=9*.169815819^2=.259536711
(I calculated w by doing 2pi/37seconds)
a_t^2=r*theta=9*(-.22)^2=.4356
(I used the given deceleration as theta, but I'm not sure if that works)
so a= sqrt((.259536711^2)+(.4356^2))= .507
As you can see I got a...
Homework Statement
The given information is:
A Ferris wheel with a radius of 9.0 m rotates at a constant rate, completing one revolution every 37 s.
Suppose the Ferris wheel begins to decelerate at the rate of 0.22 rad/s^2 when the passenger is at the top of the wheel.
(1) Find the...