Recent content by fleabass123

Homework Statement A 31.0 kg child runs with a speed of 2.80 m/s tangential to the rim of a stationary merry-go-round . The merry-go-round has a moment of inertia of 520 kg\cdot m^2 and a radius of 2.51 m. When the child jumps onto the merry-go-round, the entire system begins to rotate...

That was right! Thank you both very much. I really appreciate it! :D

I did "arctan theta=.259536711/1.98" and I got 7.47 for theta.

"_____degrees below the direction of motion" is what the field looks like. I thought my trig function would work in that situation.

That was right! Thanks so much. If you wouldn't mind I still can't get part two. I know that a_c and a_t are perpendicular to each other, so I was thinking I should use trigonometry to find the direction of acceleration. I tried arctan(a_c/a_t), but that was no good.

Yes, I meant alpha. And I squared it because I was accidentally looking at the formula for centripetal acceleration when I was writing the tangential acceleration formula. Is that squared term the root of my problems?

I did: a= sqrt(a_c^2+a_t^2) a_c^2=r*w^2=9*.169815819^2=.259536711 (I calculated w by doing 2pi/37seconds) a_t^2=r*theta=9*(-.22)^2=.4356 (I used the given deceleration as theta, but I'm not sure if that works) so a= sqrt((.259536711^2)+(.4356^2))= .507 As you can see I got a...

Homework Statement The given information is: A Ferris wheel with a radius of 9.0 m rotates at a constant rate, completing one revolution every 37 s. Suppose the Ferris wheel begins to decelerate at the rate of 0.22 rad/s^2 when the passenger is at the top of the wheel. (1) Find the...