Recent content by floater2011
-
F
Undergrad Why are sunsets red if blue light scatters and other wavelengths are absorbed?
Thanks RedBelly, I thought you'd given up on me :) I understand the whole concept of the shorter wavelengths being scattered around more, which causes blue light to end up being directed into our eyes, enableing us to see blue lighting from up around us when looking at the sky, and not directly...- floater2011
- Post #9
- Forum: Optics
-
F
Undergrad Why are sunsets red if blue light scatters and other wavelengths are absorbed?
I have. But I guess I am not grasping it. scenario 1 : During the day, the sun is up and rays, once entering the atmosphere go through a certain amount of scattering. The smaller particles will transmit rays mostly in the longer wavelengths and reflect mostly in the shorter wavelengths...- floater2011
- Post #7
- Forum: Optics
-
F
Undergrad Why are sunsets red if blue light scatters and other wavelengths are absorbed?
But if they're transmitted and with very little scattering, then howcome we can see a http://media-cdn.tripadvisor.com/media/photo-s/01/20/84/05/the-sunset-at-sunset.jpg"spread across the sky just like the blue spread across the sky during the day? Wouldnt the longer wavelengths have to scatter...- floater2011
- Post #5
- Forum: Optics
-
F
Undergrad Why are sunsets red if blue light scatters and other wavelengths are absorbed?
I don't quite understand why we see sunsets as red/orange/yellow. We see the sky as blue because Rayleigh scattering causes the smaller particles within the atmosphere to scatter bluer wavelengths and absorb others. But if the others are absorbed, which would include the red/orange/yellow...- floater2011
- Thread
- Atmospheric Scattering
- Replies: 9
- Forum: Optics
-
F
Undergrad Why does the diffuse reflection BRDF divide by pi?
Where did you read about that? I've been looking for an explanation on google but can't seem to find one, all I find is the actual formula itself. Do you know of any books that exlain it in depth? Thanks- floater2011
- Post #3
- Forum: Optics
-
F
Undergrad Why does the diffuse reflection BRDF divide by pi?
I'm confused as to how the diffuse reflection is computed as : \frac{1} {\pi} * LightRadiance * cos(\theta) Where cos(\theta) is the angle between the light and the surface normal, and accounts for the light projected onto the surface When considering light reflecting at a point from some...- floater2011
- Thread
- Reflection
- Replies: 6
- Forum: Optics