I integrated wrt to y and got y, filled in 2x+2 and 2x2-2 into y and got -2x2 +2x +4. Then integrated with respect to x and got -2x3/3 + x2 + 4x. filled in 2 and -1 to this function and ended up with a value of 9. Which is hopefully right as iv been spending hours on this question! Also I was...
In lectures we have been doing examples of functions where dxdy is not equal to dydx so that's why i thought i couldn't do it here. I did integrate wrt y first anyway and came out with an answer of 9 which looks about right from the graph iv drawn.
By changing the limits for x did you mean...
In the question it says dxdy so doesn't this mean i have to integrate wrt to x first? And if i do have to do it that way how would I find the limits as a function of y?
Thanks for your help!
im sorry its quite hard ot get used to writing maths on the internet!
The limits i used were 2 and -1 on the left integral and 2x+2 and 2x2 -2 on the right integral.
I integrated with respect to x which just gave x, then filled in the values and got
(2x+2)-(2x2-2) which gave -2x2 +2x +4
I...
Homework Statement
Find the area of the region R bounded by the parabola y = 2x2−2
and the line y = 2x + 2 by sketching R, and evaluating the area
integral
A = (doubleintegral) R dxdy.
The Attempt at a Solution
i found the points of intersection which were -1 and 2 and sketched...