Recent content by footprints

Oh! Thank you!

Yes. I think I get it. But I still don't know how to get the answer.

Find the equation of the tangent to the curve y=x^3-7x^2+14x-8 at the point where x = 1. \text{Answer: }y = 3x -3 Find the x-coordinate of the point at which the tangent is parallel to the tangent at x = 1. I need help on the second part.

Got it. Thank you.

:confused: :confused: Sorry, but I've not learned implicit differentiation. Haven't even heard of it.

$ 4xy = y^2 + 2 \ln x How do I differentiate that?

Yeah I got it. Thank you.

Oh I see... How do you know it?

I was taught that way. How did you get 1/x?

And how would that look like? Which is f & which one is g? :confused:

y = x ln x \frac{dy}{dx} = \frac{1}{x ln x} \cdot 1 Is that correct?

Oh... Got it! Thank you!

I thought \frac{dx}{dt} = 60 cm^3/s and I've to find \frac{dV}{dt} which is 1440x?

Oh now I know why you asked me about the second equation. I always get mixed up and put ds instead of dt :grumpy: . So I got 1440x. I know that's not the final answer because there's still the x = 10 part. And I'm confused on that part.

If it shouldn't be x, can you tell me what it should be? I don't know what to do for the second equation. I just know its \frac{d\text{ something}}{dx} = 60 cm^3/s. Again, if I'm wrong please tell me what it should be.