Ok the text has an example but their sphere is solid, and the point charge is outside the sphere. I could utilize Q' which would be equal to the negative ratio of two distances times Q. Q' would have to be in a different region from the one I am calculating V for. I'll give it a go.
Thanks
They would be -Q in magnitude, where is what I'm not understanding. The book would say on the opposing side of the axis, which is where the other positive point charge lies. You said putting them in r > Ra which would be in the conductor. I guess a picture will help this I tried attaching one
Well its a sphere, so the only thing not symmetrical would be the two point charges, which is what is really bugging me about this whole thing. About the method of images, wouldn't I be placing a negative point charge opposite the positive one, which in turn is where the other positive point...
Homework Statement
An electrically neutral conducting sphere of inner radius Ra and outer radius Rb is centered on the origin. Two equal, positive point charges of magnitude Q are located on the x-axis on each side a distance d from the origin. Determine the electrical potential in the...