Well his acceleration would be 9.8 m/s2 right? I'm not sure about velocity... :(
Would you use a kinematics equation?
SE=1/2kx2
x=22.2-2.58=19.62
So you use the unstretched length instead of the total length!
Thanks again!
Am I going about this the right way?
When He leaves the balloon:
KE=PE
.5mv^2=mgh
.5(326/9.8)v^2=326(33.6)
v^2=658.66
v=25.7 m/sThe 4 is actually supposed to be 2.58. Sorry about that.
Equation for stored elastic energy- PEs=(1/2)kx2
The bungee cord develops tension when everything is...
The first equation for that would be
KE=1/2mv2
So it would be (1/2)(326/9.8)v2, right?
Don't get upset, but how would would you find velocity in this situation?
The second one would be mgh, and That is (326)(33.6-4)
So his potential would be 294 J? Is that right?
The last one would...
Spring Constants and Conservation??
Homework Statement
In the dangerous “sport” of bungee-jumping, a daring student jumps from a balloon with a specially designed elastic cord attached to his waist. The unstretched length of the cord is 22.2 m, the student weighs 326 N, and the balloon is...