Woot! PAllen, you the man! Here's what I did:
\begin{equation}
v'=\frac{x'}{t'}=\frac{\frac{x-ut}{\sqrt{1-\frac{u^2}{c^2}}}}{\frac{t-\left(\frac{u}{c^2}\right)x}{\sqrt{1-\frac{u^2}{c^2}}}}=\frac{x-ut}{t-\frac{ux}{c^2}=0.588c
\end{equation}
Done! Thank you so much! This has been bothering...
PAllen: Hmmmm... if I understand what you're saying (and I'm not certain I do!) you mean to say just do the velocity addition anyway? I'm trying to find a way around that part. As I said in my original post, I want to be able to show that v=d/t works in the rest frame, the 0.8c frame, and the...
Shouldn't the function in the denominator be subtraction? They are both traveling in the positive direction, so I would think there would be a subtraction in the numerator as well as the denominator.
I have been pondering but cannot quite resolve the following question:
Imagine two spaceships, separated by 4 light-seconds initially. Spaceship A is traveling at 0.8c and Spaceship B (the one with the lead) is traveling at 0.4c.
Clearly an external observer will see this "chase" last for...