Recent content by FriedChicken885

Okay, thank you very very very much for all of your help!

I again tried solving that solution with the system of equations: a1+a2= -a and a2 = 2a1 and I got a1 = (-1/3)a which is still incorrect despite every step seeming to be correct. Also do we need to use the numerical value for m1 at all?

I also tried it for: a2 = 2a1 and a2 = a - a1 and solved for a1 = ⅓a, but that's still the incorrect answer. Also I wonder if I'm missing something since I don't use the given value of m1.

So I went through the entire question with +x as left and +y as up, I got to the two equations a(2) = 2a(1) and -a(2) = a - a(1) and solved for a(1) = -a. Yet I got the incorrect answer, what did I do wrong?

Okay, from this point I get to a(2) = a(surface) + a(1) if a(1) is towards the left and a(2) = a(surface) - a(1) is a(1) is towards the right How would I find the direction of a(1) and go about solving it from here? Also is the previously found equation a1 = (1/2)(a2) valid?

Is it something along the line that the difference in the accelerations of m1 and the surface would be the maximum possible acceleration of m2? Since the string is fixed length, the mass 2 can't fall any faster than the length of the vertical part of the string is growing? Am I on the right...

So where I’m at so far is: 1. I found μ=0.5 based off of the fact that the system began in equilibrium, and therefore μm(1)g = m(2)g 2. ΣF(m2) = F(tension) - (m2)*g = (m2)(a2) ΣF(m1)(x) = F(friction) - F(tension) = μ(m1)*g - F(tension) = (m1)(a1x) ΣF(m1)(y) = F(normal) - (m1)*g = 0 At this...

So since the string has a constant length, the magnitude of a(m2)=a(m1), right? Also I’m a little uncertain of what’s actually happening in the system, is it correct to assume the surface accelerating because of the tension force being experienced by the pulley?

So that would mean the horizontal acceleration of m2 is 0, right?

I have this exact same question, so I think that I understand that (tension force) x cos(theta) = m2 x a2(x) and (tension force) x sin(theta) = m2 a2(y) but we aren't given the angle. How would I go about solving that?