Recent content by frisky

Thanx. I understand this now.

How do you calculate the kinetic and potential energies of the Earth at the perihelion and aphelion? Given that the Earth's orbit is nearly circular GMm/R^2 = m(v^2)/R where M = sun's mass, m = Earth's R = orbital radius so v = √(GM/R) The kinetic energy, E, would be E =...