Recent content by futurept

Homework Statement It's not a specific problem. I am just having trouble understanding the right hand rule itself and it's application. What variables do you take into account when you are orienting your hand to get the direction. For example, I understand your fingers point in the...

you guys are awesome

so, (cos(x^2+e^x))^4 f'(x)= 4cos(x^2+e^x)^3*-sin(x^2+e^x)*(2x+e^x)

yeah, i think i follow. so from your definition, f'(x)=g'(h(x))*h'(x)?

so h(x)=cos4(x2+ex) and g(x)= x2 + ex but would the cos4 part be another function by itself? So then it would be f(g(h(x))). and by definition of the chain rule it would be f '(g(h(x)))*g'(h(x))*h'(x)?

I did forget to say that the problem says not to simplify.

no it's not a typo. my answer was y'= 4cos3(-sin(x2 + ex))*(2x + ex)

Homework Statement The problem is to differentiate the function. y=cos4(x2 + ex) Homework Equations cos(x)'= -sin(x), (xn)'=n*xn-1, (ex)'=ex*x' The Attempt at a Solution Thought it would be the chain rule. Here's what I came up with: y'=4cos3(-sin(x2 + ex)(2x + ex) Is this...

Hey thanks for the help!

Homework Statement Evaluate the following indefinite integral: (2t6-3)/t3 dt The Attempt at a Solution I know I need to substitute. Tried u= t3 and found du= 3t2dt. Tried to find where du would substitute in, but found...

So what do I do then. Consider that k=mg/x? then from there I can find the force. Then set that value to F=ma?

All I'm really asking for here is the starting point. I think I can do it from there, I just don't know where to get started from.

Homework Statement A 2.0 kg mass is placed on top of a vertical spring, which compresses to a new equilibrium position; the spring is then compressed from this new equilibrium position by a distance of 0.05 m. What will be the acceleration of the mass just after the spring is released from...