Recent content by gat0man
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Direct comparison test, just need some explanation
1. In order to satisfy the conditions of the comparison test, if you want to show your original series diverges, you need something smaller or equal to. You can *guarantee* that the series you are comparing it to will be smaller by taking something with a larger coefficient than the 4j, such...- gat0man
- Post #2
- Forum: Calculus and Beyond Homework Help
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Limits of log sin equal to 0/1/infinity?
Consider: What are both of the functions doing as X-> pi/2? As you are in precalc and not expected to use l'hospital's Rule, look at the graphs of these functions and consider which has larger values as X-> pi/2 If you have a very small value in the numerator and a larger value in the...- gat0man
- Post #6
- Forum: Precalculus Mathematics Homework Help
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Analyzing a Polynomial Model for Bacterial Population Growth
Hint: Many functions modeling bacterial growth, population growth, decay, use natural logs and the inverse function of natural logs, (about as close as a hint as I can give without naming it), and exponentials. Thinking around these lines, what function involving the aforementioned general...- gat0man
- Post #15
- Forum: Calculus and Beyond Homework Help
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Analyzing a Polynomial Model for Bacterial Population Growth
Hint: Many functions modeling bacterial growth, population growth, decay, use natural logs and the inverse function of natural logs (about as close as a hint as I can give without naming it). Thinking around these lines, what function involving the aforementioned general family has a derivative...- gat0man
- Post #14
- Forum: Calculus and Beyond Homework Help
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Question on Radius of Convergence for values of x, when f(x) is x^2
See my edit :p I'm tired. Realized what I was doing wrong- gat0man
- Post #3
- Forum: Calculus and Beyond Homework Help
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Question on Radius of Convergence for values of x, when f(x) is x^2
Homework Statement This is not so much an entire problem I need help with but just a part. It is a power series where after you do the ratio test, you end up with |4x^(2)| < 1, so |x^(2)| < 1/4. Since the radius of convergence is |x-a| < R, I end up with -1/4 < x^(2) < 1/4, but because...- gat0man
- Thread
- Convergence Radius Radius of convergence
- Replies: 3
- Forum: Calculus and Beyond Homework Help