So I made a diagram and thank you for reminding that x is extension not length.
We are starting from x=0 and ending at x=?
Since h can be whatever I want I made h=0 where x=0
Therefore x=-h
So
0=.5(.80)(0)+.5(87)(x2)-.8(9.8)(x)
x=0, .18023
Length at lowest point = x + length at E1...
So if I set E1 to be when the spring is at the relaxed length then E1=0
E2 is lowest point so velocity would be zero since it stopped moving
E1=E2
0= .5mv2 + .5kx2 +mgh
0=.5(.80)(0)+ .5(87)(x)2+ (.8)(9.8)(h)
I know I need to solve for x because that is spring length but I am not sure what...
Homework Statement
A spring is attached to a ceiling, and has a relaxed length of 25cm. When a mass m=.80kg is attached to the spring it stretches to an equilibrium length of L0=34cm.
a.)Find the Spring Constant of the Spring?
b.)I lift the mass until the spring returns to its relaxed length...