Recent content by GenericHbomb

So I made a diagram and thank you for reminding that x is extension not length. We are starting from x=0 and ending at x=? Since h can be whatever I want I made h=0 where x=0 Therefore x=-h So 0=.5(.80)(0)+.5(87)(x2)-.8(9.8)(x) x=0, .18023 Length at lowest point = x + length at E1...

So if I set E1 to be when the spring is at the relaxed length then E1=0 E2 is lowest point so velocity would be zero since it stopped moving E1=E2 0= .5mv2 + .5kx2 +mgh 0=.5(.80)(0)+ .5(87)(x)2+ (.8)(9.8)(h) I know I need to solve for x because that is spring length but I am not sure what...

Homework Statement A spring is attached to a ceiling, and has a relaxed length of 25cm. When a mass m=.80kg is attached to the spring it stretches to an equilibrium length of L0=34cm. a.)Find the Spring Constant of the Spring? b.)I lift the mass until the spring returns to its relaxed length...