gentzen's latest activity
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gentzen replied to the thread I Modern View of Quantum Phenomena.I guess I found it, but I didn't write anything about how to get from one parameter to two, or that I am still confused about where I...
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gentzen replied to the thread I Violation of Bell Inequality with unentangled photons.Maybe you should also start to react with "of course" from time to time, otherwise I have little idea where I lost you, or where we...
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gentzen replied to the thread I Violation of Bell Inequality with unentangled photons.You are missing Your sign measurement operators ##S_x## and ##S_p## are no longer representable by a single state, hence you have to...
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gentzen replied to the thread I Violation of Bell Inequality with unentangled photons.Yes, of course. I guess what you didn't understand is that your ##|\alpha|^2S_x+|\beta|^2S_p## is missing those interference terms...
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gentzen replied to the thread I Violation of Bell Inequality with unentangled photons.This is an observable. Your ##S_x## and ##S_p## were observables too. Maybe to clarify, we have ##\alpha=\cos(\theta)## and...
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gentzen replied to the thread I Modern View of Quantum Phenomena.Suppose you start with the state ##|\psi_{\alpha,\beta}\rangle=\alpha |z+\rangle+\beta|z-\rangle##. Then there is a measurement that...
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gentzen replied to the thread I Violation of Bell Inequality with unentangled photons.The state is entangled, but pines-demon tried to get rid of the continuous measurement outcomes, to be closer to typical Bell...
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gentzen replied to the thread I Violation of Bell Inequality with unentangled photons.You mean, because they are not normalizable? But they are well defined in a suitable space of distributions, and one can form their...
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gentzen replied to the thread I Violation of Bell Inequality with unentangled photons.$$(\alpha|x\rangle+\beta|p\rangle)(\alpha^*\langle x|+\beta^*\langle p|)=|\alpha|^2|x\rangle\langle x|+|\beta|^2|p\rangle\langle...
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gentzen replied to the thread I Violation of Bell Inequality with unentangled photons.If you define it like this, then ##S_x## and ##S_p## are already matrices (or rather operators), basically ##S_x=\int_0^\infty dx\...
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gentzen replied to the thread I Violation of Bell Inequality with unentangled photons.It just makes it easy for me to see that the state is not time invariant. With the signs of your state, I would have been a bit less...
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gentzen replied to the thread I Violation of Bell Inequality with unentangled photons.Because the spin in the normal "measurements showing Bell's inequality violations" is constant in time. The position is not, which on...
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gentzen replied to the thread I Violation of Bell Inequality with unentangled photons.Because starting with |p>|-p> corresponds to the EPR description of the experiment (the total momentum is zero). In principle, one...
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gentzen replied to the thread I Modern View of Quantum Phenomena.It measures the spin of the particle in some specific direction, as it was initially before the bending of the beam. (I am still a bit...
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gentzen replied to the thread I Modern View of Quantum Phenomena.If I have two entangled particles in "two beams" with known fixed direction, then I want to measure their spin, not the spin of two...
