Recent content by GiantCube

Thanks. :) The Force is the horizontal portion of the acceleration, so (m*a*cos(38)) must the force to get over the friction, so sin(52)*m*g. Which would be F= sin(52)*m*g + (u*m*a*cos(38)) ... I'm fairly certain that's wrong, but not sure why...

Homework Statement A 5.57 kg box sits on a ramp that is inclined at 38.0^\circ above the horizontal. The coefficient of kinetic friction between the box and the ramp is 0.28. What horizontal force is required to move the box up the incline with a constant acceleration of 4.30 m/s^2...