A 5.57 kg box sits on a ramp that is inclined at 38.0^\circ above the horizontal. The coefficient of kinetic friction between the box and the ramp is 0.28.
What horizontal force is required to move the box up the incline with a constant acceleration of 4.30 m/s^2?
Calculation F. F=ma is important. Trig functions. Calculation of F caused by friction.
The Attempt at a Solution
I calculated the force required to move the object up the ramp using a horizontal force; m*a/cos(38), which is 23.951N.
I calculated the force caused by the μk, which is sin 52*mg, which is 12.044 N
I added these, and found the horizontal component required, which is those added/ cos 28, which gives 45.7N
I am fairly certain I'm doing this wrong though, and I would appreciate any help.