Recent content by girlphysics

Thank you so much! I finally understand. I really appreciate it.

Hey! There is no mistake, my professor talked about it in class and said there are infinitely many solutions, and that he wants us to get the 3rd solution. The second solution someone posted below. He said it is difficult to get the third. any ideas?

Help -- separation of variables problem, multiple solutions. Homework Statement Suppose that dy/dx = √y and y(0) = 0. What is y(x)? There is more than one answer to this problem. You must list five correct solutions. Homework Equations separation of Variables/ integration The...

thank you! I got A I hope its right!

No it would be rad/s^3. duh omg

(rad/s^2 )/ s so rad/s which is velocity? I don't know something in my brain isn't connecting

you can't divide acceleration/time to get velocity?

5. A force of 12 N is applied tangentially to the rim of a wheel with radius 0.70 m and rotational inertia 3.0 kg-m2. What angular acceleration results? a) 2.6 rad/s2 b) 2.8 rad/s2 c) 3.2 rad/s2 d) 3.4 rad/s2 e) none of these ____6. If the force in question #5 acts for 20 s, what will be the...

thank you cepheid and good night! : ) another successful physics night thanks to you. I hope your ok with me asking for your help until may 14th! haha. You help me understand so much better!

oh cool! I finally get it. Thank you for helping me. I understand it too! amazing! lol

2∏/120 s.= 1/60 rad/sec was I right about constant GPE or was it a nice try? lol

looking at the units, I need joules=Kg*m^2/s^2 . where will I get s^2 when I only have angular velocity

oh duh, the PE is mgh, I think I was thinking KE when I put the 1/2 in there

I suppose the GPE stays constant, because a car at the top would have let's say 100 and the car at the bottom 0, then both in the middle each 50. So because the cars are all directly across from each other, the GPE is constant.

SO 1/2ωI^2 substitute I=mr^2 so (1/2)ω(mr^2)^2 then to find ω, is it 2∏diameter/2min?