Recent content by gjt01

...perhaps it's not to late to withdraw...

if there are 10 shoes, and you take away 4, logically you would always have at least one pair left, but no more then three. Or am I understanding your question entirly wrong?

The rectangle would have to be perpendicular to the Force. Since the force is at 60 degrees, perpendicular would be 110 degree. If I made a rectangle it wouldn't be perpendicular. So I wouldn't know how to go about doing that. I considered projecting downward from Point A and forming a right...

On the first problem, what throws me off is the force. I've solved problems where there were two forces on a pivot. Thats done by making the Triangle and using sin and cosine laws. But I don't see how this one would be done the same. If it was a force of 120-N and 200-N, at those angles, I...

Heres the first two problems.

Would it be easier if I just scanned the 4 problems and sent the pictures?

Wow... spaces don't work in this forum... ummmm fom the center point, there is a line going 120 mm at 132 degrees, and a line moving 200 mm at 40 degrees and the force is 400-N at 20 degrees off point A. Point A is the end of the 200 mm line, B is the end of the 120mm line, and O is the axis.

ok... not really sure how since there is a picture... anyways 1)A 400-N force P is applied at point A off the bell crank shown. (a) Compute the moment of the force P about O resolving it's components. A B / /...

I need urgent help in Statics I'm taking a Statics course in college right now. However, I wasn't able to get a book due to financial issues early on. Naturally I feel behind. Anyways, I have a test coming up and the teacher gave us four problems to solve as a study guide, saying similar...