Recent content by gkamal

Yes it is right but just to make sure the B of I3 becomes positive because it's value is negative and it is point in the -x , thus it would be point in the +x with a positive value since 2 negatives cancel right? btw thank you so much for your help

-2.48x10^-5 T in the i direction and -4.66x10^-5 in the j direction

actually the -4.66x10^-5 is negative not positive i just edited it like 2 sec b4 ur reply i hope this was the mistake

you're right it should be -2.48x10^-5 T in the i direction and -4.66x10^-5 in the j direction right?

This gives me -2.48x10^-5 T in the i direction and 2.48x10^-5 in the j direction does this look correct ?

ok so Bx should be in the in the +x direction and By should be in the -y direction right ? i guess i mixed them while going fast

I'm sorry that the image is flipped but i tried uploading the pic multiple times but it still not straight , and I'm down to my last try so please look carefully at my work cause otherwise I'm getting 0 on this questions and it counts for a lot.Thanks for your help.Btw i don't get why I had to...

ok so this is what i did and i got -4.66x10^-5 T in the i direction and 4.66x10^-5 in the j direction but the machine keeps telling me that I'm wrong ,

yeah , sorry about that i'll do it next time

so now i do the same steps which subtracting the -x value from the +x value and adding the 2 -y values together ? if that was correct i get : -4.66x10^-5 T in the i direction and 4.66x10^-5 in the j direction sorry for the late reply i had a cal final exam so i didn't have the time for physics

so By should be negative and Bx should be positive ?

i'm sorry but my calculations are a real mess and if i take a picture and post it here it won't help u in the slightest but here , i got 1.56 for the angle which is oddly small which is why i tried again and got 45 for the angle and now my values are : Bx = 1.09 x 10^-5 By = 1.09 x 10^-5

i did what is mentioned above and then i used these fomulas Bx = Bsin(x) and By = Bcos(x)

what i got for B2x and B2y is what i said above , the stuff using the tangent and all that and the 1.54x10^-5 is the magnitude of B2 4.19x10^-7 for Bx and 1.53x10^-5 for By

i got 1.54x10^-5 , but if this is right everything else is correct ? i just follow the same steps using these new values or...