Recent content by grahas

I was watching a movie called Everything and Nothing. It got me thinking. For the sake of argument pretend that you could make the sun pop in and out of existence. If you were to measure the distance between two points on the other side of the solar system with no sun, then if the sun were to...

Current in a strip of graphene can be calculated with following equation. w is the width of the strip V is the voltage on the two ends of the strip l is the length of the strip $$A=1.60217662\times10^{-19}C\times w\times \frac{10^{12} }{cm^{2}}\times \frac{V}{l}\times \frac{200000cm^{2}}{Vs}...

Good to know. I am going to try and write a python program to find the variables that maximize force and are feasible to manufacture. For the community I will write up the conclusion of the post into a little nugget that might be useful.

The strip will be about 3000 meter long, 300000 cm. So E = 50 V / 300000 cm = 1.666x10-4 V/cm . Then vd = 200,000 cm2/( V s) x 1.666x10-4 V/cm = 33.33 cm / s vd = 33.33 cm / s Electron / surface density = 1012 /cm2 width = 4x10-5 elementary charge = 1.60217662 × 10-19 coulombs Current =...

I think that I got that the voltage to cancel out whe calculating the drift velocity. 200,000 cm^2/( V s) * 1V . Another question, how much voltage could this strip take before it broke? And just checking, electric field strength is measured in voltage right? Also how would the length impact the...

Where did the 1 meter come from? I am going to cut the graphene from a sheet into a really long skinny wire so it will be a lot longer than 1 meter. Also is E just the voltage being applied to the wire? I just set E to equal 1 volt to make calculations easy.

I got 0.00000128A. Is that the same as what you got?

I came up with an answer. PLEASE don't just gloss over it. The math needs to be done correctly. I came up with 1.28A. Using the following variables. Voltage is equal to 1V, electron mobility is equal to 200,000cm2 /(s*V), Electron density is 1012/cm2 I had a question about that number; since the...

Ok I am stuck. Really sorry I don't have a formal education, I had to read wikipedia for answers. When I researched (googled, youtubes, and wikipedia) all I found is that electron density is the probability of finding an electron in a region in an atom. Original I thought it was the amount of...

Sorry for long wait, I am still trying to figure this out.

This is not homework. I trying to get the attention of a research group and need to have some ballpark estimates for what I am going to need their help to build. I don't have the background in these physics to really do this my self, I don't have any teachers or anyone to get help from, also I...

Hi, I need to calculate the current in a 400nm piece of graphene. Can some one help me please? I found online that graphene has electron mobility of 200,000 cm^2/( V s). My best attempt is as follows. Using the equation vd = uE where E is the magnitude of the electric field applied to a...

Well I got an answer but I am not positive it is correct. The bold black line represents the area accumulated of the top half of one leaf. An approximation of the area of the top half of the east leaf with a triangle gives a value of 0.075 and the bold black line has a value of 0.08. I think...

Still haven't been able to solve it. Sorry. I think I will just try to solve it numerically in python.

I have been trying it for a while. I can't figure out how to convert the polar graph to a parametric one. I tried internet resources but they weren't to great. Is there any other way to solve this without converting it to parametric?