Hmm..
T - 1.18 = 1N
T = 2.18N / 9.81m/s^2 = 0.222kg
Same answer I had before. It's not right because when I verify:
(0.222*9.81) - 1.18 = 1 / (0.222 + 1) = 0.81
Acceleration has to be 1.00m/s^2 and not 0.81.
Fr is frictional force. Yes I know my mistake was that it is the same direction as the net force. Indeed the pulley is massless and frictionless. This is what I do so that the force of friction is different from the net force:
-Fnet = (x) - 1.18
-1N = (x) - 1.18
x = 0.18N
0.18N/9.81 = 0.018kg...
Homework Statement
Homework Equations
F=ma, Fr = μN
The Attempt at a Solution
1kg(1m/s^2) = 1N
Fnet = (x) - 1.18
1N = x - 1.18
x = 2.18N
2.18N/9.81m/s^2 = 0.223kg
I know this is not right because I was told that in my calculations Fnet and Fr go in the same direction. Also I didn't use...