Recent content by Graxum
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Can a human calculate this without a calculator?
ey, the preview seems to be messed up. whenever i click "preview" it doesn't change anything and i have to reload the page in order to get it to work, and when i turn off preview mode i lose a bunch of stuff i wrote.- Graxum
- Post #5
- Forum: Calculus and Beyond Homework Help
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Can a human calculate this without a calculator?
my notebook says that we can rewrite the integral $$\int {75\sin^3(x) \cos^2(x)dx}$$ as $$\int {75 \cos^2(x)\sin(x)dx} - \int {75\sin(x)\cos^4(x)dx}$$ however, i have literally no idea how it got to this point, and i unfortunately can't really provide an "attempt at a solution" for this...- Graxum
- Thread
- Calc 1 Calculator Human Integral Trigonometry
- Replies: 11
- Forum: Calculus and Beyond Homework Help
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Find the two points on the curve that share a tangent line
Ah i completely forgot about that! I have 1 more question though, After the correction I got 2 answers ##(a= -1/sqrt3, b= 1/sqrt3)## from the left side and ##(a=-1, b=1)## from the right side, how do I check which of those is the correct answer? are both correct? in that case, when I plot the...- Graxum
- Post #7
- Forum: Calculus and Beyond Homework Help
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Find the two points on the curve that share a tangent line
IMPORTANT: NO CALCULATORS I assumed two points, (a, f(a)) and (b, f(b)) where b is greater than a. Since the tangent line is shared, I did f'(a) = f'(b): 1) 4a^3 - 4a - 1 = 4b^3 - 4b - 1 2) 4a^3 - 4a = 4b^3 - 4b 3) 4(a^3 - a) = 4(b^3 - b) 4) a^3 - a = b^3 - b 5) a^3 - b^3 = a - b 6) (a...- Graxum
- Thread
- Calculus Curve Differentiation Line Points Tangent Tangent line
- Replies: 9
- Forum: Calculus and Beyond Homework Help