I found this on your forum:
If velocity is (-) (down or to the left) and x (motion) is speeding up, then acceleration will have a (-) sign in front of it.
If velocity is (+) (up or to the right) and x (motion) is slowing down, then acceleration will have a (-) sign in front of it.
So my...
Upon initial contact with the ground the sign should be positive, i would think. When the ball hits the ground it is 0. As the ball moves upward, gravity is working on it again, but the ball is moving positively. What am I doing wrong here? It's just not clicking. I hope I'm close though thanks.
do you mean initial velocity should be: v(initial) = sqrt(2*-9.8m/s^2*-2.5m) = 7m/s
and then final velocity would be the same, if so then am i right about the direction being down because the average acceleration is - ? Thanks for helping.
[b]1. A ball is dropeed from a height of 2.5m and rebounds to a height of 2.1m. If the ball is in contact with the floor for .70ms determine 1: direction and 2: the magnitude of the balls average acceleration due to the floor
I know the equation for average acceleration = change in...