Recent content by grint

Equation: k' = k[OH- ]^n k' and [OH-] measured / calculated Log both sides of the equation above log k' = log (k[OH- ]^n ) log k' = log k + n log([OH- ] which is the same as log k' = n log([OH- ] + log k Which you can look at as y = mx + b m = n, therefore slope = n, n = 1.04 calculate k...

http://imgur.com/IgOdMW3 Question in the link. How do I go from here and get the rate constant and n values?

I believe one of the equations is wrong, you forgot a square. a_2(\theta- 2\pi/3)+ 2= 3/4 the part in the parenthesis should be squared