Recent content by gsg822

I forgot that I could substitue Vsin(15) for Voy. I think I may have gotten the answer. Vsin(15) = 5.2 / 2Vcos(15) Rearranged that to V2 = 5.2 / (2sin(15)cos(15)) V = sqrt(5.2 / (2sin(15)cos(15))) V = 3.22 m/s Plug that value back into the Vox and Voy equations to get: Vox =...

I have two variables, V and Voy. 0 = Voy(0.534m / Vsin(15)) - (1/2)(9.8m/s2)(0.534m / Vsin(15))2 (1/2)(9.8m/s2)(0.285m / (Vsin(15)2) = Voy(0.534m / Vsin(15)) 2.79m2/s2 / ( Vsin(15)2) = 2Voy(0.534m / Vsin(15)) 2.79m2/s2 / ( Vsin(15)) = 2Voy(0.534m) I get stuck here and don't know...

When you say to use the y equation are you referring to y = y0 + voy * t - 0.5 * g * t2. I've tried using this equation and I get stuck when I try and simplify it down. I solved the x equation for time and got t = 0.534m / (V * sin(15))

Homework Statement I need help finding the x and y components of initial velocity being given the angle the trajectory was fired at and the distance the projectile traveled. For this example I'm using an angle of 15° and the projectile travels 0.534m. I'm not sure if I'm going in the right...