Recent content by Gumbosplat

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    Sciene fair project, freefall stuff - need one equation for time

    How would I be able to estimate that? I'm not able to actually measure that, and I don't know how to calculate that anyway. Could I also base force calculations off of the distance traveled into the ground after collision? I'd estimate that to be around 0.0001m on a hardwood floor, just a guess.
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    Sciene fair project, freefall stuff - need one equation for time

    Posting new calculations for 0.2m d=0.2m a=9.8m/s/s m=0.0567kg t=√2d/a t=√0.4m/9.8m/s/s t=√0.04s/s t=0.2s v=at v=9.8m/s/s*0.2s v=1.96m/s KE=1/2 m v^2 KE=0.028kg*3.841m^2/s^2 KE=0.108J
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    Sciene fair project, freefall stuff - need one equation for time

    I'm going to calculate KE, and then force from that
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    Sciene fair project, freefall stuff - need one equation for time

    Is there an equation I should be using? I'm really at a loss as to what to even begin with.
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    Sciene fair project, freefall stuff - need one equation for time

    Hm, I don't think I can measure that accurately...
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    Sciene fair project, freefall stuff - need one equation for time

    Measuring the bounce height is part of my experiment, and I have recorded those heights. Do you mean you can't find the force without factoring in the total time? I thought that you could just use F=m(Δv/Δt) for just the way down, would this be inaccurate?
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    Sciene fair project, freefall stuff - need one equation for time

    Thank you so much! Now I have to kick myself all day for forgetting the velocity formula, you really just made my day, though. Are you sure that the air resistance would be significant at this small of a height?
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    Sciene fair project, freefall stuff - need one equation for time

    Homework Statement Ok, so I'm doing this science fair project on tennis ball bounce hieght, and I have to find the force that it hits the ground with. I'm trying to do this mathematically, because I can't record the time accurately in the actual experiment. The mass of the ball is 0.0567kg...