hi all
∑F x= 400cos30 – 600 cos36.87 + F1 sinØ =0
∑F y= 400sin30 – 600sin36.87 + F1 cosØ =0
R=√(〖fx〗^2+〖fy〗^2 )
800=√((〖298.35+f1sinØ)〗^2+〖(560+f1 cosØ)〗^2 )
As we see ; we have two equation and two unknown so we can get the magnitude and direction of f1
Hi All
to get magnitude of resultant use cosin rule R^2= X^2+Y^2 – 2XYcosβ
to get the direction use sine rule = (Sin β /length of opposite line) = (sinθ/ length of opposite line)