Recent content by Hema

Thanks! Would you please explain to me how we can define the subsystem without the pulley and only the straight sections of cord above and below? Won't that just give the equation T.Va + T.Vc = 0?

I tried it again and got it, thanks for your help!

If Vwg is the hypotenuse then I suppose Vsq would be 3, and the component would be 3 * cos x = 12/5.. but it can have many other values as well right?

It is not possible for x to be 90 degrees right? In that case 4 would be the hypotenuse and 5 one of the sides, which is not possible as the hypotenuse is always longest. I'm so sorry for the late reply by the way, something went wrong with my internet connection.

But is x is 90 degrees he doesn't have to walk across right? He can just reach the opposite side- he won't be drifting at all

This is the result I get.. for horizontal distance traveled on opposite bank to be minimum component of Vsg must be minimum along horizontal.. which will be when cos x = 0 or x is a right angle.. but in that case Vsw will be hypotenuse.. where did I go wrong?

Homework Statement Under the action of force P the constant acceleration of B is 6 m/s^2 up the incline as in figure. For the instant when B's velocity is 3 m/s up incline, what is the velocity of point C? How do I solve this using constraints? [/B] Homework Equations For a pulley system ΣT.v...

What is a minimization problem? No, I don't think I have learned them. I have only studied a few relative velocity of swimmer type problems. Yes, you are right, I suppose my assumption is wrong. But the only other way for this to follow Pythagoras theorem is for Vsw to be perpendicular to Vsg...

Homework Statement A river of width 4 km flows at 5 km/h. A swimmer whose speed relative to water is 4 km/h, starts swimming from a point A on a bank. What minimum distance will the swimmer have to walk on the other bank to reach point B directly opposite to A? [/B]Homework Equations Vba = Vb...